Question

the diagonal of a rhombus measure 16cm and 30cm find its perimeter​

Answer 1

Answer:

68 m

Step-by-step explanation:

The perimeter of a rhombus is the total measure of its boundary and it is calculated by adding the length of all its sides. Since all the four sides of a rhombus are equal, the basic formula to find the perimeter of a rhombus is: Perimeter = 4a; where 'a' is the side of the rhombus.

Ncert solutions

Our top 5% students will be awarded a special scholarship to Lido.

Set your child up for success with Lido, book a class today!

Mathematics

Science

Chapters in NCERT Solutions - Mathematics, Class 7

Exercises in The Triangle and its properties

Question 17

The diagonals of a rhombus measure 16 cm and 30 cm. Find its Perimeter.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

ANSWER:

Let PQRS be a rhombus, all sides of rhombus has equal length and its diagonal PR and SQ are intersecting each other at a point O. Diagonals in rhombus bisect each other at 90° .

So, PO = (PR/2)

= 16/2

= 8 cm

And, SO = (SQ/2)

= 30/2

= 15 cm

Then, consider the triangle POS and apply the Pythagoras Theorem,

PS2 = PO2 + SO2

PS2 = 82 + 152

PS2 = 64 + 225

PS2 = 289

PS = √289

PS = 17 cm

Hence, the length of side of rhombus is 17 cm

Now,

Perimeter of Rhombus = 4 × Side of the Rhombus

= 4 × 17

= 68 cm

∴ Perimeter of Rhombus is 68 cm.PS2 = 289

PS = √289

PS = 17 cm

Hence, the length of side of rhombus is 17 cm

Now,

Perimeter of rhombus = 4 × side of the rhombus

= 4 × 17

= 68 cm

∴ Perimeter of rhombus is 68 cm.

Answer 2

Step-by-step explanation:

ANSWER:

Let PQRS be a rhombus, all sides of rhombus has equal length and its diagonal PR and SQ are intersecting each other at a point O. Diagonals in rhombus bisect each other at 90° .

So, PO = (PR/2)

= 16/2

= 8 cm

And, SO = (SQ/2)

= 30/2

= 15 cm

Then, consider the triangle POS and apply the Pythagoras Theorem,

PS2 = PO2 + SO2

PS2 = 82 + 152

PS2 = 64 + 225

PS2 = 289

PS = √289

PS = 17 cm

Hence, the length of side of rhombus is 17 cm

Now,

Perimeter of Rhombus = 4 × Side of the Rhombus

= 4 × 17

= 68 cm

∴ Perimeter of Rhombus is 68 cm.PS2 = 289

PS = √289

PS = 17 cm

Hence, the length of side of rhombus is 17 cm

Now,

Perimeter of rhombus = 4 × side of the rhombus

= 4 × 17

= 68 cm

∴ Perimeter of rhombus is 68 cm.Then, consider the triangle POS and apply the Pythagoras Theorem,

PS2 = PO2 + SO2

PS2 = 82 + 152

PS2 = 64 + 225

PS2 = 289

PS = √289

PS = 17 cm

Hence, the length of side of rhombus is 17 cm

Now,

Perimeter of Rhombus = 4 × Side of the Rhombus

= 4 × 17

= 68 cm

∴ Perimeter of Rhombus is 68 cm.PS2 = 289

PS = √289

PS = 17 cm

Hence, the length of side of rhombus is 17 cm

Now,

Perimeter of rhombus = 4 × side of the rhombus

= 4 × 17

= 68 cm

∴ Perimeter of rhombus is 68 cm.Then, consider the triangle POS and apply the Pythagoras Theorem,

PS2 = PO2 + SO2

PS2 = 82 + 152

PS2 = 64 + 225

PS2 = 289

PS = √289

PS = 17 cm

Hence, the length of side of rhombus is 17 cm

Now,

Perimeter of Rhombus = 4 × Side of the Rhombus

= 4 × 17

= 68 cm

∴ Perimeter of Rhombus is 68 cm.PS2 = 289

PS = √289

PS = 17 cm

Henre, the length of side of rhombus is 17 cm

Now,

Perimeter of rhombus = 4 × side of the rhombus

= 4 × 17

= 68 cm

∴ Perimeter of rhombus is 68 cm.