The diagonal of a rhombus measures 16cm and 30cm.Find its perimeter .Do this by pithagorus formulae. Plz give me the answ er!!!
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as we know that the diagonals of rhombus bisect each other at 90 degree
so , by usong Pythagoras theOrem
16÷2×16÷2+30÷2×30÷2=side×side
8×8+15×15=side ×side
64+225=side ×side
side=√289
side =17cm
all the sides of a rhombus are equal
so perimeter of rhombus=17×4=68cm
so , by usong Pythagoras theOrem
16÷2×16÷2+30÷2×30÷2=side×side
8×8+15×15=side ×side
64+225=side ×side
side=√289
side =17cm
all the sides of a rhombus are equal
so perimeter of rhombus=17×4=68cm
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