Question

The diagonal of a rombus is 16 cm and 30 cm respectively . Find its perimeter .​

Answer 1

Answer:

The perimeter of the Rhombus is 68 cm.

Answer 2

Hi mate

Once you helped me and now is my time to prove that I can help

Question given to solve

The diaognal of a rombas is 16 cm and 30 cm respectively. Find its Perimeter.

Answer-

First let us draw a rough figure for understanding it better.(in attachment)

Here I have marked it with points like ABCD

Now,

In the figure

Diagonals AC=30cm

Diagonal DB=16cm.

Since the diagonals of the rhombus bisect at right angle to each other.

$therefore \: od = \frac{db}{2}$

$= \frac{16}{2}$

$= 8$

$and \: oc = \frac{ac}{2}$

$= \frac{30}{2}$

$= 15$

Now, In right angle triangle DOC,

According to the pythogoras theorum

$({dc})^{2} = ({od})^{2} + ( {co})^{2}$

$= > ({dc})^{2} = ({8})^{2} + ( {15})^{2}$

$= > ({dc})^{2} = 64 + 225$

$= > ({dc})^{2} = 289$

$= > dc = \sqrt{289} = 17$

So therefore DC=17cm

Yay!!!

We finally found out the value dc that is 17 cm

Now,

We know,

Perimeter of the rhombus=4× side

So therefore

Perimeter of the rhombus=4× side

=4×17=68cm

Thus, the perimeter of rhombus is 68 cm.

Hope it helps you mate!!