the diagonal of a square field is 90 M what is its area
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8
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→area of square = side *side
→as diagonal is given , so we can use another formula of area of square
→ area of square=
⇒where d is diagonal
⇒so, 90²÷2
⇒ 8100/2
⇒4050
∴ your answer is 4050
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Answered by
4
Let the square be ABCD whose each side measures 'x '.
The two perpendiculars are AC and BD.
AB = BD = 90 m (diagnols of a square are equal in length).
In triangle ABC , angle B = 90° (all angles of a square are right angles).
(Use Pythagoras theorem)
AC² = AB² + BC²
(90 m)² = (x )² + (x )²
2x² = 8100 m²
x² = 4050 m²..........1
Area of a square = side²
= x²
Substitute the value of x² from eq 1
= 4050 m²
Ans. = 4050 m²
Hope it helps! ^^
The two perpendiculars are AC and BD.
AB = BD = 90 m (diagnols of a square are equal in length).
In triangle ABC , angle B = 90° (all angles of a square are right angles).
(Use Pythagoras theorem)
AC² = AB² + BC²
(90 m)² = (x )² + (x )²
2x² = 8100 m²
x² = 4050 m²..........1
Area of a square = side²
= x²
Substitute the value of x² from eq 1
= 4050 m²
Ans. = 4050 m²
Hope it helps! ^^
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