Question

The diagonal of a square is 12 cm long. Find its area and perimeter

Answer 1

Let side of square be x
Therefore, Diagonal of square = x√2(By Pythagoras theorem)
$x \sqrt{2} = 12 \\ x = \frac{12}{ \sqrt{2} } \\ x = 6 \sqrt{2}$
Area =
$6 \sqrt{2} \times 6 \sqrt{2} = 72 {cm }^{2}$
Perimeter=4 × side
= 4 × 6√2
24√2cm

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Answer 2

HEYA_______

YOUR ANSWER________

ANSWER :
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AREA = 144cm^2

PERIMETER = 48cm


GIVEN :
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Diagonal of square = 12 cm


TO FIND :
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Area and Perimeter of square


SOLUTION :
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Area of square is (side)^2 = a^2

We know that ,
{ If diagonals of a square is given then area of square will be a^2 = d^2 }

Area of square = (12)^2

a^2 = 144

a = √144

a = 12

Hence the side of square is【12 cm】

Perimeter of square = 4×a

4 × 12 = 48 cm

【 AREA OF SQUARE = 144cm^2 】

【 PERIMETER OF SQUARE = 48cm】



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