Question

The diagonal of a square is 12 to the root 2. Find the perimeter.

Answer 1

нєуα

нєяє ιѕ тнє αиѕωєя

∂ιαgσиαℓ σf α ѕqυαяє = 12√2 υиιт

αℓѕσ, ∂ιαgσиαℓ = ѕι∂є × √2

ѕσ,

ѕι∂є × √2 = 12√2

ѕι∂є = 12 υиιт.

ρєяιмєтєя σf ѕqυαяє = 4 × ѕι∂є

=> 4 × 12

=> 48 υиιт.

нσρє тнιѕ нєℓρѕ.

Answer 2

We know diagonal of a square is $\sqrt{2}a$ where a is the side of the square

Given :

$\sqrt{2}a=12\sqrt{2}$

Cancelling $\sqrt{2}$ on both sides we get:-

So:

$a=12$

Perimeter =4 a

$\implies 4*12$

$\implies 48$

The perimeter is 48 units

Hope it helps.