Question

the diagonal of a square is 42cm. the diagonal of another square whose area is double that of the first square is?

Answer 1

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Answer 2

Answer:

$42\sqrt2\text{ cm}$

Step-by-step explanation:

If d is the diagonal of a square then the area is given  by

$A=\frac{1}{2}d^2$

Hence, the area of the first square is given by

$A=\frac{1}{2}(42)^2\\\\A=882 cm^2$

Let the diagonal of second square is x

Now, the area of the second square is double of the first square. Hence, area of the second square is 2×882 = 1764 square centimeter.

Hence, we have

$1764=\frac{1}{2}x^2\\\\x^2=3528\\x=42\sqrt2$

Hence, the diagonal of second square is $42\sqrt2\text{ cm}$