Question

the diagonal of a square is 5√2 units . find its perimeter​

Answer 1

The perimeter of the square is 20 cm and area is 25 sq. cm.

The perimeter of the square is 20 cm and area is 25 sq. cm.Explanation:

The perimeter of the square is 20 cm and area is 25 sq. cm.Explanation:A square has all its side equal.

The perimeter of the square is 20 cm and area is 25 sq. cm.Explanation:A square has all its side equal.The measure of all interior angles in square is 90°.

The perimeter of the square is 20 cm and area is 25 sq. cm.Explanation:A square has all its side equal.The measure of all interior angles in square is 90°.Diagonal of square make right angle triangle.

The perimeter of the square is 20 cm and area is 25 sq. cm.Explanation:A square has all its side equal.The measure of all interior angles in square is 90°.Diagonal of square make right angle triangle.Let a be the side-length of the square.

The perimeter of the square is 20 cm and area is 25 sq. cm.Explanation:A square has all its side equal.The measure of all interior angles in square is 90°.Diagonal of square make right angle triangle.Let a be the side-length of the square.If the diagonal of a square is 5√2 cm.

The perimeter of the square is 20 cm and area is 25 sq. cm.Explanation:A square has all its side equal.The measure of all interior angles in square is 90°.Diagonal of square make right angle triangle.Let a be the side-length of the square.If the diagonal of a square is 5√2 cm.Then, by Pythagoras theorem , we have

The perimeter of the square is 20 cm and area is 25 sq. cm.Explanation:A square has all its side equal.The measure of all interior angles in square is 90°.Diagonal of square make right angle triangle.Let a be the side-length of the square.If the diagonal of a square is 5√2 cm.Then, by Pythagoras theorem , we have\begin{gathered}

• a^2+a^2=(5\sqrt{2})^2\\\\ 2a^2=50\\\\ a^2=25\\\\ a=5\end{gathered}
• a^2+a^2=(5\sqrt{2})^2\\\\ 2a^2=50\\\\ a^2=25\\\\ a=5\end{gathered} a
• 2 +a =2 a
• =(52)
• ) 2

) 2

• ) 2 2a
• ) 2 2a 2
• ) 2 2a 2 =50
• ) 2 2a 2 =50a
• ) 2 2a 2 =50a 2
• ) 2 2a 2 =50a 2 =25
• ) 2 2a 2 =50a 2 =25a=5

) 2 2a 2 =50a 2 =25a=5

) 2 2a 2 =50a 2 =25a=5

) 2 2a 2 =50a 2 =25a=5 Thus , the side of square is 5 cm

) 2 2a 2 =50a 2 =25a=5 Thus , the side of square is 5 cmThen, Perimeter of square = 4(side) = 4(5) = 20cm

) 2 2a 2 =50a 2 =25a=5 Thus , the side of square is 5 cmThen, Perimeter of square = 4(side) = 4(5) = 20cmArea of square = (side)² =(5)² = 25 sq. cm

) 2 2a 2 =50a 2 =25a=5 Thus , the side of square is 5 cmThen, Perimeter of square = 4(side) = 4(5) = 20cmArea of square = (side)² =(5)² = 25 sq. cmHence, the perimeter of the square is 20 cm and area is 25 sq. cm.

Answer 2

Answer:

20 units

Step-by-step explanation:

Given, Diagonal of square = $5\sqrt{2}$

We know, diagonal of square = $a\sqrt{2}$ (where a is the side of the square)

So,

                   $a\sqrt{2}$ = $5\sqrt{2}$

                       a = 5 units

Perimeter of square = 4a

                                 = 4 x 5

                                 = 20 units

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