Question

The diagonal of a square is 8 cm,
then what is the length of its side​

Answer 1

To find :

• The length of its side

Given:

• Diagonal = 8 cm

Full solution :

★Consider that the side of the square is x cm.

Since the diagonal are the perpendicular bisectors,

$∙→$Then with the help of Pythagoras theorem :

$\sf: \: ↦ \: {x}^{2} + {x}^{2} = {8}^{2}$

$\sf : \: ↦ \: 2 {x}^{2} = 64$

$\sf: \: ↦ \: {x}^{2} = 32$

$\sf: \:↦ \: x = \sqrt{32}$

$\sf: \: ↦ \: x = \sqrt[4]{2}$

$\fbox{ \red{{: \: ↦ \: \: x = 5.66 \: cm}}}$

✧Main Answer

Length of its side will be 5.66 cm

Answer 2

✦ Question :

The diagonal of square is 8cm, then what is the length of its side.

✦ Given :

• Diagonal of square = 8cm

✦ To find :

• Length of its side

✦ Solution :

• Consider that the side of the square is x cm.

• Since the diagonals are the perpendicular bisectors, then by Pythagoras theorem,

➣ x² + x² = 8²

➣ 2x² = 64

➣ x² = 64/2

➣ x² = 32

➣ x = √32

➣ x = 4√2

➣ x = 5.66cm

➨ Therefore, length of side of Square = 5.66 CM.