Question

the diagonal of a square is
$12 \sqrt{?} 2 cm$
find its perimeter

Answer 1

Diagonal of square = root2a²
$= > \sqrt{2} {a}^{2} = 12 \sqrt{2} \\ = > {a}^{2} = 12 \\ = > a = \sqrt{12} \\ = > a = 4 \sqrt{3}cm$


Perimeter of square = 4a
$= > 4a = 4 \times 4 \sqrt{3} \\ = > 4a = 16 \sqrt{3}cm.$


So,
Required answer is
$16 \sqrt{3}cm.$



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