Question

the diagonal of a square measure 7√4cm find its area​

Answer 1

Answer:

Answer:

It is given that diagonal BD= 4 cm(See the enclosed figure)

Let each side of the square be 'a'.

Here, ∆BAD and ∆BCD are right triangles (ABCD is a square).

Now, applying Pythagoras theorem in ∆ABD,

(Hypotenuse)²= (Base)²+(Perpendicular)²

(BD)²= (AB)²+(AD)²

(4)²= (a)²+(a)²--------(All the sides of a square are equal )

16= 2a²

16÷2= a²

8= a²

2√2 cm= a

Thus, each side of the square is of length 2√2 cm

Now, Area of a square= a² where a is the side

=> (2√2)²

=> 4×2

=> 8 cm²

Answer 2

Answer:

97.64cm square

Step-by-step explanation:

diagonal of square=7√4

= 7*2

=14

√2 a=14

a= 14/√2

a=9.88

area =a*a

=9.88*9.88

=97.64cm square