Question

The diagonal of a square named A is (x+y).Find the diagonal of a square named B whose area is twice the area of this square named A????

Answer 1

In the attachment, I have solved this problem.

I hope that the answer will be easy
to understand.
.
.
Karups

Answer 2

ANSWER :

The diagonal of a square A is (a+b). The diagonal of a square whose are is twice the area of square A, is

[A]\sqrt{2}(a-b)

[B]\sqrt{2}(a+b)

[C]2(a+b)^{2}

[D]2(a+b)

\mathbf{\sqrt{2}(a+b)}

Area of the square A = \frac{\left ( diagonal \right )^{2}}{2}= \frac{\left ( a+b \right )^{2}}{2}

Area of the new square

= \frac{\left ( a+b \right )^{2}}{2}\times 2 = \left ( a+b \right )^{2}

=> side = (a+b)

\therefore Diagonal = \sqrt{2}\times side

= \sqrt{2}(a+b)..

HOPE IT WILL HELP YOU ✌