Question

The diagonal of a square PQRS is a+b. The perimeter of a square with twice the area of PORS is 9​

Answer 1

Answer:

Area of the square A = $latex \frac{\left ( diagonal \right )^{2}}{2}= \frac{\left ( a+b \right )^{2}}{2}&s=1$

Step-by-step explanation:

Area of the new square

$latex = \frac{\left ( a+b \right )^{2}}{2}\times 2 = \left ( a+b \right )^{2}&s=1$

$latex => side = (a+b)$

$latex \therefore Diagonal = \sqrt{2}\times side$

$latex = \sqrt{2}(a+b)$

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