Question

The diagonal of AC of a quadilaterl ABCD
is 6 cm and its perpendicular BM from the vertex B is 3 cm and DN from D is 5 cm dropped on the same diagonal find the area of quadrilateral ABCD​

Answer 1

Answer:

Given : Length of the diagonal (AC)=10 cm

Area of quadrilateral ABCD=ar(△ABC)+ar(△ACD)

=(

2

1

×AC×BM)+(

2

1

×AC×DL)

=

2

1

×AC(BM+DL)

=

2

1

×10(5+6)

=5×11cm

2

=55cm

2

Answer 2

Answer:

Area of the quadrilateral = 24

Step-by-step explanation:

From the given data ,

area =$\frac{1}{2} * d_{1} *d_{2}$

$\frac{1}{2} * 48 = 24cm^{2}$