The diagonal of cube is √12cm .what is hength of its edge.
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diagonal of cube is √12 = 2√3
as we know
![diagonal of cube = a\sqrt{3} diagonal of cube = a\sqrt{3}](https://tex.z-dn.net/?f=diagonal+of+cube+%3D++a%5Csqrt%7B3%7D+)
where a is edge of cube
then
![2 \sqrt{3} = a \sqrt{3} <br /><br /> then a = 2 2 \sqrt{3} = a \sqrt{3} <br /><br /> then a = 2](https://tex.z-dn.net/?f=2+%5Csqrt%7B3%7D++%3D+a+%5Csqrt%7B3%7D+%3Cbr+%2F%3E%3Cbr+%2F%3E%C2%A0+then++a+%3D+2)
thus length (edge) of cube is 2 units
as we know
where a is edge of cube
then
thus length (edge) of cube is 2 units
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