The diagonal of parallelogram PQRS intersect at O.PL and RM are perpendicular on diagonal SQ. Prove that PL=RM
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Answer:
in angle PQS
ar (triangle PSB) = ar( triangle PBQ) ---- (i)
in angle SOQ
ar(triangle SBO)=ar (triangle OBQ) ----- (ii)
= ar (triangle PSB) + ar( traingle SBO) = ar(triangle PBQ)+ ar( triangle OBQ)
= ar( triangle PSO) = ar (triangle PQU)
Step-by-step explanation:
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