Question

the diagonal of quadrilateral is 20 m in length and the perpendicular to it from the opposite vertices 8.5 cm and 11 m Find the area of the quadrilateral

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Answer 1

Answer:

Diagonal(d)= 20m

Perpendiculars, ($p_{1}$)=8.5cm= 0.085m

                           ($p_{2}$)=11m

Area of quadrilateral=$\frac{1}{2} (p_{1} +p_{2} )d$

                                  =$\frac{1}{2} (0.085+11)20$

                                  =110.85$m^{2}$

Step-by-step explanation:

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