Question

The diagonal of quadrilateral shaped field is 24 m and the perpendicular dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Answer 1

Step by step explanation

Answer 2

Question :-

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Given :-

• Diagonal of quadrilateral = 24m

• opposite vertics = 8m and 13m

To find :-

• Area of field ?¿

Solution :-

Area of the field = area of ∆ABD + area of ∆BCD

$= \dfrac{1}{2} \times b \times h + \dfrac{1}{2} \times b \times h$

$= \dfrac{1}{2} \times 24 \times 13 + \dfrac{1}{2} \times 24 \times 8$

$= 12 \times 13 + 12 \times 8$

$= 12 \times (13 + 8)$

$= 12 \times 21$

$= {252m}^{2}$

Hence, the required area of the field

$= {252m}^{2}$