The diagonal of quadrilateral shaped field is 24m and the perpendiculars dropped
on it from the remaining opposite vertices are 10m and 15m. Find the area of the
field..
give step by step explanation
Answers
Answered by
16
Answer :-
- The area of quadrilateral-shaped field is 300m².
Step-by-step explanation:
To Find :-
- The area of a quadrilateral-shaped field
Solution:
Given that,
- The diagonal of quadrilateral shaped field is 24m
- The perpendiculars dropped the diagonal from the remaining opposite vertices are 10m and 15m
As we know that,
Area of quadrilateral = [ 1/2 × d × ( h₁ + h₂ ) ] sq. units,
Where,
- d = diagonal of quadrilateral-shaped field.
- h₁ and h₂ are perpendiculars dropped the diagonal from the remaining opposite vertices
Therefore,
=> [ 1/2 × 24 × ( 10 + 15 ) ] m²
=> [ 1/2 × 24 × 25 ] m²
=> [ 1 × 12 × 25 ] m²
=> [ 12 × 25 ] m²
=> 300m²
Hence, The area of quadrilateral-shaped field is 300m².
Answered by
38
Question :-
- The diagonal of quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 10m and 15m. Find the area of the field.
Given :-
- Shape of Field = Quadrilateral
- Height of Quadrilateral = 24m
- First perpendicular = 10m
- Second perpendicular = 15m
To Find :-
- Area of the Quadrilateral
Solution :-
➞ Area = ½ × H × (sum of perpendicular)
➞ Area = ½ × 24 × ( 10 + 15 )
➞ Area = 12 × ( 10 + 15 )
➞ Area = 12 × 25
➞ Area of the Field = 300m²
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Therefore, Area of the Field = 300m²
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