The diagonal of rectangle ABCD meets at O. If angle BCD=40°, Then find angle OAD.
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Answer:
angle BOC=angle A O D. (vertically opposite angle)
so,
angle AOD =40
in triangle AOD,
angle OAD= angle ODA. (opp angles of Iso. Tri.)
angle A O D + angle OAD + angle ODA= 180
40+angle OAD + angle OAD=180
2(angle OAD)=140
angle OAD=70
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