the diagonal of rectangle is 26cm and breadth is10cm . find the length of rectangle
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by Pythagoras theorem
diagonal ²=breadth ²+length ²
26²=10²+l²
l²=26²-10²=(26-10)(26+10)=16×36
l=√(16×36)=4×6=24cm
diagonal ²=breadth ²+length ²
26²=10²+l²
l²=26²-10²=(26-10)(26+10)=16×36
l=√(16×36)=4×6=24cm
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