Question

the diagonal of rhombus measure 14 cm and 48 cm . find its perimeter

please solve this plz​

Answer 1

we know that the diagonal of a rhombus bisect each other at right angles ......

now ...

oB =48/2=24cm

OC=14/2=7cm

therefore.....

BC(hypotenuse)

$= \sqrt{24 {}^{2} + 7 {}^{2} } \\ = 25 \: \: cm$

therefore the side of the cube is =25 cm

so... perimeter=(4×25)cm=100cm