Math, asked by mammtas123, 11 months ago

The diagonal of Rhombus Measure 14 cm and 48 CM . find its
parimeter

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Answered by Sufiyan4813
0
 {h }^{2} = {b }^{2} + {hight }^{2}
48/2=24
14/2=7
 {h }^{2} = 576 + 49 \\ {h}^{2} = 625 \\ h = \sqrt[2]{625 } \\ h = 25side \\ primeter \: of \: rombos = 4 \times side \\ 4 \times 25 = 100 \\ 100ans

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Answered by aishmoundekar
1
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