Question

The diagonal of sqare is 4√2.the diagoal of another square whose area is double that of the first square is?

Answer 1

Area of a first square = side × side

$= (4 \sqrt{2)} {}^{2} \\ = 64$
Area of second triangle = side × side
$64 = x \times x \\ x = \sqrt{64} = \sqrt{16 \times 4 } \\ = 8$