Question

the diagonal of the diagonal of a rhombus measure 16cm and 30cm find its perimeter​

Answer 1

Answer:

102 cm

Step-by-step explanation:

let ABCD be that rhombus

for finding parimeter we need to find ab

AC diagonal 1=16 cm half of AC =8 cm

BD diagonal 2=30 cm half of BD=15cm

let the point where AC and BD meets be O

AOB forms a triangle and ∠O=90°

by the pythagores theorem

AB²=AO²+OB²

AB²=8²+15²

AB²=64+225

AB=√64+225

AB=√8²+15²

AB=8+15

=23 cm

perimeter=4Side

=4*23

=102 cm