Question

the diagonal of the rectangle abcd intersect at o.if angle cod=78 then angle oab is​

Answer 1

Answer:

51 deegree

Step-by-step explanation:

hope it helps you........

Answer 2

The value of  ∠ OAB = 51°

Given: The diagonal of the rectangle ABCD intersects at O.

           ∠ COD = 78°

To Find: ∠ OAB

Solution:

• We know that in a rectangle, the intersection of the two diagonals at some point 'O', divides each diagonal into two equal parts.

Hence, in the rectangle ABCD,

                     OA = OB                                   .... (1)

Also, it is said that ∠ COD = 78°

So, ∠ AOB = 78°       [ Vertically opposite angles are equal ]

Now, since OA = OB, we can say that;     [from (1)

         ∠ OAB = ∠OBA = x°                          [ Isosceles triangle ]

In Δ OAB,

         ∠ OAB + ∠OBA + ∠ AOB = 180°      [Total angles in a triangle=180°]

   ⇒ x + x + 78° = 180°

   ⇒   2x = 102°

   ⇒   x  = 102°/2

             = 51°

Hence, the value of  ∠ OAB = 51°

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