Question

The diagonal passing through origin of a quadrilateral formed by x=0, y=0, x+y=1x=0, y=0, x+y=1 and 6x+y=3,6x+y=3, is

Answer 1

6×0+0=3
6×0+0=3

0=6 (adding the two equation)

therefore the diagonal formed is (0,6)

Answer 2

Given:

x=0, y=0, x+y=1 and 6x+y=3

Solution:

(0, 0) is the one end of the diagonal.

The intersection of the other two lines, x + y = 1and 6x + y = 3 is (2/5, 3/5) which is the other end of the diagonal. The equation of the line that passes through these two points is 3x - 2y = 0.

Therefore the correct equation will be 3x - 2y = 0.