The diagonal PR and QS of a rectangle PQRS intersect each other at A. If angle RSQ=40 degree , find angle PAQ.
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According to the question,
PQRS is a rectangle, and A is the intersection point of diagonals PR and SQ.
So,
PR = SQ (Diagonals of a rectangle are equal])
and, RA = SA (Diagonals of a rectangle bisect each other)
∴∠ASR =∠ARS =40° (Angles opposite to equal sides are equal)
Thus, ∠SAR = 180° - (40 + 40)° = 180° - 80° = 100°
Now, since PR and SQ are diagonals of a rectangle.
Then, PR and SQ bisect each other at A
Thus, ∠SAR = ∠PAQ = 100° (vertical angles are equal)
Ans) ∠PAQ = 100°
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