The diagonals AC and BD of a parallelogram
ABCD intersect each other at the point O such that
DAC = 30' and ZAOB -70". Then, DBC = ?
(a) 35°
(b) 45°
(c) 50°
(d)40°
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DBC =40' (option d is correct)
Step-by-step explanation:
DAC=ACB=30'(alternative interior angle)
and BOC+AOB=180'(both angles in straight line)
so BOC=180'-70'
BOC=110'
and. BOC+OCB+OBC=180'(sum of all angles of a triangle is 180')
BOC+ OCB+DBC=180'
110'+30'+DBC=180
DBC=180'-140'
DBC=40'.
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