Math, asked by raishivansh6, 11 months ago

The diagonals AC and BD of a parallelogram
ABCD intersect each other at the point O such that
DAC = 30' and ZAOB -70". Then, DBC = ?
(a) 35°
(b) 45°
(c) 50°
(d)40°




Answers

Answered by vinayjindal234
3

Answer:

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Answered by vaibhav605632
3

Answer:

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DBC =40' (option d is correct)

Step-by-step explanation:

DAC=ACB=30'(alternative interior angle)

and BOC+AOB=180'(both angles in straight line)

so BOC=180'-70'

BOC=110'

and. BOC+OCB+OBC=180'(sum of all angles of a triangle is 180')

BOC+ OCB+DBC=180'

110'+30'+DBC=180

DBC=180'-140'

DBC=40'.

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