Question

the diagonals AC and BD of a parallelogram ABCD intersect each other at the point of O . if angle DAC=34° and angle AOB=75° then angle DBC is equal to?​

Answer 1

Answer:

valla valla valla valla valla valla

Answer 2

Answer:

DBC = 38

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Step-by-step explanation:

In given figure,

Quadrilateral ABCD is a parallelogram.

So, AD ∣∣ BC

∴ ∠DAC = ∠ACB --- ( Alternate angle)

∴ ∠ACB = 32

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∠AOB + ∠BOC = 180

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--- (straight angle)

⇒70

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+ ∠BOC = 180

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∴ ∠BOC = 110

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In △BOC,

∠OBC + ∠BOC + ∠OCB = 180

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⇒∠OBC + 110

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+ 32

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= 180

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⇒ ∠OBC = 38

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∴ ∠DBC = 38

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