Question

The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If DAC = 42o and AOB = 90o , then find the value of DBC.​

Answer 1

Answer:

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Answer 2

Answer:

In given figure,

Quadrilateral ABCD is a parallelogram.

So, AD ∣∣ BC

∴ ∠DAC = ∠ACB  --- ( Alternate angle)

∴ ∠ACB = 32∘

∠AOB + ∠BOC = 180∘  --- (straight angle)

⇒70∘ + ∠BOC = 180∘

∴ ∠BOC = 110∘

In △BOC,

∠OBC + ∠BOC + ∠OCB = 180∘

⇒∠OBC  + 110∘ + 32∘ = 180∘

⇒ ∠OBC = 38∘

∴  ∠DBC = 38∘