Question

The diagonals AC and BD of a parallelogram ABCD intersect at O. If P is the
mid-point of AD, prove that:
(i) PQ || AB
(ii) PO = CD

Answer 1

Answer:

Given:

Step-by-step explanation:

ABCD is parallelogram

AC and BD are digonal intesect at O

so DO =BO

AO=CO

And P is the midpoint of AD side

so AP=DP

let Q is the midpoint of BC side

So

BQ=CQ

AD=BC ( opposite side are equal in parallelogram )

Po=QO

So

PO=QO=1/2PQ

we draw PQ

Proof: 1). PQ=AB

2) PO=CD

Now,

In the Quadrilateral PQCD

PD=QC

And PD||QC.

so

PQCD is parallelogram

so PQ||CD

hence proved

I hope you understand

Answer 2

Step-by-step explanation:

hope it helps you

thank you

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