the diagonals AC and BD of a parallelogram ABCD intersect at O if P is the midpoint of a d prove that PO =1/2CD
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PO =1/2CD
Proved below.
Step-by-step explanation:
Given:
Since ABCD is a ∥gm , the two diagonals bisect each other. So O is the mid point of AC.
A shown in the figure given below, In triangle ABD, P is the mid point of AD and O is the mid point of BD.
So, OP∥AB (mid point theorem)
Also,
Since AB=CD
Hence
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