Math, asked by shivampal430012, 1 year ago

The diagonals AC and BD of a parallelogram ABCD meet at O. From midpoint of AD,a line MH is drawn parallel to DB meeting AO at H and line MK parallel to AO meeting DO at K. Prove that area of parallelogram MHOK is equal to one 1/16 of area of parallelogram ABCD

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Answered by amanmishra05050
38

I hope you understand from this answer.


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