The diagonals AC and BD of a rectangle ABCD intersect at O. Write the sides which are equal to show that angle AOB = angle COD.
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Answer:
Step-by-step explanation:
IN TRIANGLE AOB AND COD
AB=CD
ANGLECAB=ANGLEDCA
ANGLE DBA=ANGLECDB
THEREFORE THEY ARE CONGRUENT
BY CPCT THESE ANGLES ARE EQUAL
OR EVEN BY VERTICALLY OPPOSITE ANGLES PROPERTY THEY ARE EQUAL
THANK YOU
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