Math, asked by mamatamahanta89, 6 months ago


The diagonals AC and BD of a rectangle ABCD intersect each other at P. If
ZABD = 50°, find ZDPC.​

Answers

Answered by Devilchicken
7

Answer: 80 degree

Step-by-step explanation:

Given: Angle ABD = Angle ABP = 50

Angle PBC + Angle ABP = 90  (Each angle of a rectangle is a right angle)

Angle PBC = 40

Now, PB = PC  (Diagonals of a rectangle are equal and bisect each other)

Therefore,

Angle BCP = 40  (Equal sides has equal angles)

In triangle BPC,

Angle BPC + Angle PBC + Angle BCP = 180 (Angle sum property of a triangle)

Angle BPC = 100

Angle BPC + Angle DPC = 180  (Angles in a straight line)

Angle DPC = 180 - 100 = 80 degree.

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Answered by coolapoorva
3

Answer:

here it is..... hope it will help you

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