Question

The diagonals AC and BD of a rectangle ABCD intersect each other at P. If
ZABD = 50°, find ZDPC.​

Answer 1

Answer: 80 degree

Step-by-step explanation:

Given: Angle ABD = Angle ABP = 50

Angle PBC + Angle ABP = 90  (Each angle of a rectangle is a right angle)

Angle PBC = 40

Now, PB = PC  (Diagonals of a rectangle are equal and bisect each other)

Therefore,

Angle BCP = 40  (Equal sides has equal angles)

In triangle BPC,

Angle BPC + Angle PBC + Angle BCP = 180 (Angle sum property of a triangle)

Angle BPC = 100

Angle BPC + Angle DPC = 180  (Angles in a straight line)

Angle DPC = 180 - 100 = 80 degree.

Answer 2

Answer:

here it is..... hope it will help you