The diagonals AC and BD of a rectangle ABCD intersect each other at P. If
ZABD = 50°, find ZDPC.
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Answered by
7
Answer: 80 degree
Step-by-step explanation:
Given: Angle ABD = Angle ABP = 50
Angle PBC + Angle ABP = 90 (Each angle of a rectangle is a right angle)
Angle PBC = 40
Now, PB = PC (Diagonals of a rectangle are equal and bisect each other)
Therefore,
Angle BCP = 40 (Equal sides has equal angles)
In triangle BPC,
Angle BPC + Angle PBC + Angle BCP = 180 (Angle sum property of a triangle)
Angle BPC = 100
Angle BPC + Angle DPC = 180 (Angles in a straight line)
Angle DPC = 180 - 100 = 80 degree.
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Answer:
here it is..... hope it will help you
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