Question

The diagonals AC and BD OF A RHOMBUS ABCD meet at O if AC = 8CM, BD = 6CM . Find sin angle OCD

Answer 1

Answer:

Diagonals of a Rhombus perpendicularlly bisect each other

=> AO  = OC  = AC/2  = 8/2 = 4 cm

Similalrly

BO  = OD  = BD/2  = 6/2   = 3 Cm

in Δ OCD

OC = 4 cm

OD = 3 cm

CD² = OC² + OD²

=> CD² = 4² + 3²

=> CD² = 25

=> CD = 5 cm

sin ∠OCD  = OD/CD

=> Sin∠OCD  = 3/5

Step-by-step explanation:

Hope this helps you