Math, asked by bond7662, 9 months ago

The diagonals AC and BD of a trapezium ABCD intersect at O such that DO:OB= 1:2, then Ab =2cd , cd =2ab , ac =2bd , BD =2ac

Answers

Answered by parikhichi

8

ANSWER

2(AB+BC+CA+AD)>2(AC+BD)
2(AB+BC+CA+AD)>2(AC+BD)
(AB+BC+CA+ AD)>(AC+BD).
(AC+BD<(AB+BC+CA+AD)

Answered by TSGarmy

0

Answer:

Ab=2cd

Step-by-step explanation:

ab=2cd is the right answer

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