Math, asked by PanduDeepak4260, 1 year ago

The diagonals AC and BD of cyclic quadrilateral ABCD intersect at E perpendicularly. From the point E the perpediculat to meet DC at F provethat DF=FC

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Answered by swarn1730

1

Answer:

bfbdjxnbxjs by zjcbuxnzhz

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