Question

The diagonals AC and BD of parallelogram ABCD intersect at the point O. If DAC = 34º and
| AOB = 75°, then DBC =
]
1) 15°
2)41°
3) 35°
4) 25°​

Answer 1

Answer:

ABCD is a parallelogram .

∴ AD | | BC ⇒ ∠ACB = ∠DAC = 34°

Now, ∠AOB is an exterior angle of △BOC

∴ ∠OBC + OCB = ∠AOB [∵ ext ∠ = sum of two int. opp. ∠S]

⇒ ∠OBC + 34° = 75°

⇒ ∠OBC = 75° - 34° = 41°

or ∠DBC = 41°

Answer 2

Answer:

the answer of this question is 35 degree