Question

the diagonals are AC and BD . show that the diagonals have the same midpoint ​

Answer 1

Answer:

be P be the mid point of AC

by midpoint formula

x=2+(-1)/2

x=1/2

y=3+(-2)/2

y=1/2

therefore P(x,y)=(1/2,1/2)

be Q be the mid point of BD

by midpoint formula

x=3+(-2)/2

x=1/2

y=-1+2/2

y=1/2

therefore Q(x,y)=(1/2,1/2)

as P=Q

therefore

we can say that the diagonals have the same mid point