The diagonals of a |gm ABCD intersect at a point 0. Through 0, a line is
drawn to intersect AD at P and BC at Q. Show that PQ divides the
parallelogram into two parts of equal area.
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- Let (x, y) be the centroid of triangle ABC
- Then, x= - 1+5+8/3=12/3=4
- y=0-2+2/3=0/3=0
- Therefore,
- The centroid of triangle ABC
- is (4,0).
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