The diagonals of a parallelogram bisect each other proof
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yes bisect each therefore u are right
Dik11dreamer:
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Hey Here's ur answer ,
PROOF :
Angle EAD = Angle ECB ---------(alternate angles) --------
Angle EDA = Angle EBC ---------(alternate angles) ----------
Angle AED = Angle CED ----------(opposite angles) ---------
AD = BC --------------------------------(opposite sides of a parallelogram are equal)--------
Triangle DEA is congruent to triangle BEC------ (angles are equal and two corresponding sides are equal) ------
CE = AE --------(corresponding sides of congruent triangles)-----
Therefore diagonal AC is bisected.
BE = ED -------(corresponding sides of congruent triangles)-----
Hence diagonal AC is bisected.
QED
(Figure is in the pic )
Hope it helps you !
PROOF :
Angle EAD = Angle ECB ---------(alternate angles) --------
Angle EDA = Angle EBC ---------(alternate angles) ----------
Angle AED = Angle CED ----------(opposite angles) ---------
AD = BC --------------------------------(opposite sides of a parallelogram are equal)--------
Triangle DEA is congruent to triangle BEC------ (angles are equal and two corresponding sides are equal) ------
CE = AE --------(corresponding sides of congruent triangles)-----
Therefore diagonal AC is bisected.
BE = ED -------(corresponding sides of congruent triangles)-----
Hence diagonal AC is bisected.
QED
(Figure is in the pic )
Hope it helps you !
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