Question

The diagonals of a quadrilateral ABCD intersect each other at point O. Show that AO/BO = CO/DO.
Please help me ​

Answer 1

Answer:

Proved.

Step-by-step explanation:

∠DOC = ∠AOB (Vertically opposite angles are equal)

since AB || DC,

∠DOC = ∠OAB (Alternate angles are equal)

∴ By AA corollary of similar triangles.

∴ △OAB ~ △OCB When the two triangle are similar, the side are proportionally.

⇒ OA/OC = OB/OD

Hence proved.