Math, asked by ashhadhusain2004, 3 months ago

The diagonals of a quadrilateral ABCD intersect each other at the point o such that
CO
BO DO
Show that ABCD is a trapezium.
Similarity of Triangles​

Answers

Answered by yasar777
2

Answer:

Given: Quadrilateral ABCD in which diagonals AC and BD intersects each other at O such that AO/BO = CO/DO. Construction: Through O, draw line EO, where EO || AB, which meets AD at E. ⇒ AB || DC. Hence, quadrilateral ABCD is a trapezium with AB || CD.

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