Math, asked by nandinivc, 1 year ago


The diagonals of a quadrilateral are perpendicular. Show that the quadrilateral formed by
joining the mid-points of its sides is a rectan

Answers

Answered by nhkmk786
1
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Given AC,BD are diagonals of a quadrilateral ABCD are perpendicular. P,Q,R and S are the mid points of AB,BC, CD and AD respectively.Proof: In  ΔABC, P and Q are mid points of AB and BC respectively. ∴ PQ|| AC and PQ = ½AC ..................(1) (Mid point theorem)Similarly in ΔACD, R and S are mid points of sides CD and AD respectively. ∴ SR||AC and SR = ½AC ...............(2) (Mid point theorem) 
From (1) and (2), we get PQ||SR and PQ = SR Hence, PQRS is parallelogram ( pair of opposite sides is parallel and equal)

Now, RS || AC and QR || BD.

Also, AC ⊥ BD (Given)

∴RS ⊥ QR. 

Thus, PQRS is a rectangle.

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Answered by HarshaTalluri
2

Answer:

Given AC,BD are diagonals of a quadrilateral ABCD are perpendicular.

P,Q,R and S are the mid points of AB,BC, CD and AD respectively.

Proof:

In  ΔABC, P and Q are mid points of AB and BC respectively.

∴ PQ|| AC and PQ = ½AC ..................(1) (Mid point theorem)

Similarly in ΔACD, R and S are mid points of sides CD and AD respectively.

∴ SR||AC and SR = ½AC ...............(2) (Mid point theorem)

From (1) and (2), we get

PQ||SR and PQ = SR

Hence, PQRS is parallelogram ( pair of opposite sides is parallel and equal)

Now, RS || AC and QR || BD.

Also, AC ⊥ BD (Given)

∴RS ⊥ QR.  

Thus, PQRS is a rectangle.

Step-by-step explanation:

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