The diagonals of a quadrilateral are perpendicular. Show that the quadrilateral formed by
joining the mid-points of its sides is a rectan
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Given AC,BD are diagonals of a quadrilateral ABCD are perpendicular. P,Q,R and S are the mid points of AB,BC, CD and AD respectively.Proof: In ΔABC, P and Q are mid points of AB and BC respectively. ∴ PQ|| AC and PQ = ½AC ..................(1) (Mid point theorem)Similarly in ΔACD, R and S are mid points of sides CD and AD respectively. ∴ SR||AC and SR = ½AC ...............(2) (Mid point theorem)
From (1) and (2), we get PQ||SR and PQ = SR Hence, PQRS is parallelogram ( pair of opposite sides is parallel and equal)
Now, RS || AC and QR || BD.
Also, AC ⊥ BD (Given)
∴RS ⊥ QR.
Thus, PQRS is a rectangle.
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Answer:
Given AC,BD are diagonals of a quadrilateral ABCD are perpendicular.
P,Q,R and S are the mid points of AB,BC, CD and AD respectively.
Proof:
In ΔABC, P and Q are mid points of AB and BC respectively.
∴ PQ|| AC and PQ = ½AC ..................(1) (Mid point theorem)
Similarly in ΔACD, R and S are mid points of sides CD and AD respectively.
∴ SR||AC and SR = ½AC ...............(2) (Mid point theorem)
From (1) and (2), we get
PQ||SR and PQ = SR
Hence, PQRS is parallelogram ( pair of opposite sides is parallel and equal)
Now, RS || AC and QR || BD.
Also, AC ⊥ BD (Given)
∴RS ⊥ QR.
Thus, PQRS is a rectangle.
Step-by-step explanation:
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