Question

the diagonals of a quadrilateral are perpendicular to each other and their lengths are 18 cm and 20cm name the quadrilateral
write the formula for finding its area
what is the area of this Quadrilateral​

Answer 1

Answer:

Since the diagonals of the given quadrilateral are perpendicular its a Rhombus.

Formula :

$\frac{1 }{2} \times d1 + d2$

where; d1 = diagonal no.1

d2 = diagonal no. 2

$\frac{1}{2} \times d1 + d2 \\ \frac{1}{2} \times 18 + 20 \\ here \: 2 \: and \: 18 \: get \: cancelled \: and \: 18 \: becomes \: 9 \\ 9 + 20 = 29 {cm}^{2}$

Therefore, the area of the quadrilateral is 29 sq.cm