Question

The diagonals of a quadrilateral shaped field is 24 m and the perpendicular dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

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Answer 1

Hey Dear ... ✌️

=) Area of Quadrilateral :-

$\frac{1}{2} \times diagonal \times (sum \: of \: perpendibular \: of \: diagonals)$

$\frac{1}{2} \times 24 \times (8 + 13) {m}^{2} \\ \frac{1}{2} \times 24 \times 21 {m}^{2} \\ 12 \times 21 \\ 252 {m}^{2}$

Hope , It Helps ... ❤️

Answer 2

Question :-

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field ?

Given :-

• Diagonal of field = 24m

• Opposite vertics = 8m , 13m

To find :-

• Area of field ?¿

Solution :-

Area of the field = area of ∆ABD + area of ∆BCD

= $\dfrac{1}{2}$ × b × h + 12 × b × h

= $\dfrac{1}{2}$ × 24 × 13 + 12 × 24 × 8

= 12 × 13 + 12 × 8

= 12 × (13 + 8)

= 12 × 21

= 252 ${m}^{2}$

Hence, the required area of the field

= 252 ${m}^{2}$