Question

The diagonals of a rectangle ABCD intersect at o. If angle BOC= 70°. find angle ODA.​

Answer 1

Step-by-step explanation:

Since in a rec diagonal are equal and bisect each other

∴OD=OA

and ∠S opp to equal sides are equal

∴∠1=x

Now, In ΔODA

∠DOA=70° (vertically opp. ∠S)

x+∠1+70=180°(∠ sum prop)

and ∠1=x

∴x+x+70=180

2x=110

x= 110/2

x=55°

⇒ ∠ODA=55°

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Answer 2

Step-by-step explanation:

Answer

• Since in a rec diagonal are equal and bisect each other

∴OD=OA

• and ∠S opp to equal sides are equal ∴∠1=x

Now,

In ΔODA

∠DOA=70 /0

(vertically opp. ∠S)

x+∠1+70=180° /0

(∠ sum prop)

and ∠1=x

∴x+x+70°=180°

2x=110

x = 2/110

x=55° /0

⇒ ∠ODA=55°/0

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