the diagonals of a rectangle abcd intersect at o. if angle boc=44degrees ,find angle oad
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44° as vertically opposite angle
Vatsal1234:
sorry it's wrong
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Hola Mate !!
Here's your answer :-
In a rectangle, diagonals are equal bisect each other at equal parts.
In triangle AOD,
ang. 0AD = ang. ODA { ▪ angles opposite to equal sides of a triangle are equal }........1
ang. AOD = 44° { ▪ Vertically opposite angle }...........2
Now,
ang. AOD + ang. OAD + ang. ODA = 180° { ▪ angles sum property of a triangle }
=> ang. AOD + ang. OAD + ang. OAD = 180° [ from 1 ]
=> 44° + 2 OAD = 180° [ from 2 ]
=> 2 OAD = 180° - 44°
=> 2 OAD = 136°
=> OAD = 136°/2
=> ang. OAD = 68° [Ans.]
Hope it helps
Mark me as brainliest if it's correct
Here's your answer :-
In a rectangle, diagonals are equal bisect each other at equal parts.
In triangle AOD,
ang. 0AD = ang. ODA { ▪ angles opposite to equal sides of a triangle are equal }........1
ang. AOD = 44° { ▪ Vertically opposite angle }...........2
Now,
ang. AOD + ang. OAD + ang. ODA = 180° { ▪ angles sum property of a triangle }
=> ang. AOD + ang. OAD + ang. OAD = 180° [ from 1 ]
=> 44° + 2 OAD = 180° [ from 2 ]
=> 2 OAD = 180° - 44°
=> 2 OAD = 136°
=> OAD = 136°/2
=> ang. OAD = 68° [Ans.]
Hope it helps
Mark me as brainliest if it's correct
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